A basketball player hits three-point shots 41% of the time. If she takes 4 shots during a game, what is the probability that she misses the first shot and hits the last three shots.
|
A basketball player hits three-point shots 41% of the time. If she takes 4 shots during a game, what is the probability that she misses the first shot and hits the last three shots.
P(miss 1st, hits 2nd, hits 3rd, hits 4th) = P(miss first) x P(hits 2nd) x P(hits 3rd) x P(hits 4th)
Can you work out each of them?
| All times are GMT -7. The time now is 08:18 AM. |