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New Member
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Feb 18, 2010, 03:21 PM
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a perfect cubical die is thrown,then find the probability of getting a six.
a perfect cubical die is thrown,then find the probability of getting a six.
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Uber Member
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Feb 19, 2010, 12:51 AM
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A probability of something happening is always the number of ways you can get your desired outcome divided by the number of ways you can get any outcome.
How many ways are there to get that six? One die - how many six's on it?
And how many possible things are there to get if you throw it?
Then divide.
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New Member
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Jun 24, 2010, 07:36 PM
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Assuming the die has pips of 1-6 with opposite sides totaling 7, one sixth is your probability.
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Uber Member
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Jun 27, 2010, 04:21 AM
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Parlaydog, the thread is from February. The search drags up a lot of old posts so you need to kind of watch the dates.
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Uber Member
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Jul 1, 2010, 09:19 AM
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 Originally Posted by Parlaydog
Assuming the die has pips of 1-6 with opposite sides totaling 7, one sixth is your probability.
I get a total of 6, not a total of 7... and if you had seven, the probability would be 1/7
:confused:
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New Member
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Oct 7, 2011, 04:01 AM
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The sum of the opposite sides of a die are 7, 1+6, 2+5, 3+4
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Uber Member
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Oct 7, 2011, 04:53 AM
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Ah okay, but that wasn't at all the question here...
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