a perfect cubical die is thrown,then find the probability of getting a six.

A probability of something happening is always the number of ways you can get your desired outcome divided by the number of ways you can get any outcome.

How many ways are there to get that six? One die - how many six's on it?

And how many possible things are there to get if you throw it?

Then divide.

Assuming the die has pips of 1-6 with opposite sides totaling 7, one sixth is your probability.

Parlaydog, the thread is from February. The search drags up a lot of old posts so you need to kind of watch the dates.

Quote:

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Originally Posted by Parlaydog

Assuming the die has pips of 1-6 with opposite sides totaling 7, one sixth is your probability.

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I get a total of 6, not a total of 7... and if you had seven, the probability would be 1/7
:confused:

The sum of the opposite sides of a die are 7, 1+6, 2+5, 3+4

Ah okay, but that wasn't at all the question here...