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mako451 · Apr 20, 2011, 10:11 PM

(cotx-tanx)/(cosx+sinx) = (cosx-sinx)/(sinxcosx)

I'm sooooo lost thank you

ebaines · Apr 21, 2011, 06:24 AM

Originally Posted by mako451

(cotx-tanx)/(cosx+sinx) = (cosx-sinx)/(sinxcosx)

im sooooo lost thank you

First, make the substitution cot(x) = cos(x)/sin(x) and tan(x) = sin(x)/cos(x). This gives you

$<br /> \frac {\frac {\cos x} {\sin x} - \frac {\sin x} {\cos x} }{\cos x + \sin x} = \frac {(\cos x - \sin x )} {\sin x \cos x}<br />$

Now cross-multiply, and you're essentially done.