(cotx-tanx)/(cosx+sinx) = (cosx-sinx)/(sinxcosx)




I'm sooooo lost thank you

Quote:

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Originally Posted by mako451

(cotx-tanx)/(cosx+sinx) = (cosx-sinx)/(sinxcosx)

im sooooo lost thank you

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First, make the substitution cot(x) = cos(x)/sin(x) and tan(x) = sin(x)/cos(x). This gives you



Now cross-multiply, and you're essentially done.