(cotx-tanx)/(cosx+sinx) = (cosx-sinx)/(sinxcosx) I'm sooooo lost thank you
Quote: Originally Posted by mako451 (cotx-tanx)/(cosx+sinx) = (cosx-sinx)/(sinxcosx) im sooooo lost thank you First, make the substitution cot(x) = cos(x)/sin(x) and tan(x) = sin(x)/cos(x). This gives you Now cross-multiply, and you're essentially done.