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rcrd67 · Feb 24, 2011, 11:28 PM

galactus · Feb 25, 2011, 04:27 AM

It may be easier to differentiate, if you rewrite the log.

$ln\left(\sqrt{\frac{x-5}{6x-9}}\right)=\frac{1}{2}\left[ln(x-5)-ln(6x-9)\right]$

Now, it should be easier to find the derivative.

$\frac{d}{dx}\left[\frac{1}{2}ln(x-5)\right]=\frac{1}{2(x-5)}$

$\frac{d}{dx}\left[ln(6x-9)\right]=\frac{d}{dx}[ln(3(2x-3))]=\frac{d}{dx}[ln(3)+ln(2x-3)]=\frac{1}{2x-3}$

Now, put them together.

$\frac{1}{2(x-5)}-\frac{1}{2x-3}=\frac{7}{2(x-5)(2x-3)}$