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geometrical optics
A small object is located 30.6 cm in front of a concave mirror with a radius of curvature of 40.9 cm.
So the question is Where will the image be formed? I thought I use this equation to solve 1/do + 1/di= 1/f I solved for R by using f=(1/2)R and got 20.45 I then plug that in with all my information. However the answer I get isn't right. What am I doing wrong? |
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