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-   -   Geometrical optics (https://www.askmehelpdesk.com/showthread.php?t=548220)

  • Jan 26, 2011, 08:10 PM
    heyyalliee
    geometrical optics
    A small object is located 30.6 cm in front of a concave mirror with a radius of curvature of 40.9 cm.

    So the question is Where will the image be formed?

    I thought I use this equation to solve 1/do + 1/di= 1/f

    I solved for R by using f=(1/2)R and got 20.45
    I then plug that in with all my information. However the answer I get isn't right. What am I doing wrong?

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