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    Ranya's Avatar
    Ranya Posts: 3, Reputation: 1
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    #1

    Nov 14, 2010, 09:51 PM
    (1 cosu)/(1-cosu) - (1-cosu)/(1 cosu) = 4cotucscu
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Nov 14, 2010, 10:58 PM

    1. Combine the two fractions on the left hand side.
    2. Use the difference of two squares; , on the denominator.
    3. Expand the numerator.
    4. Simplify.

    You should get there fast enough.
    Ranya's Avatar
    Ranya Posts: 3, Reputation: 1
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    #3

    Nov 15, 2010, 06:28 AM
    cosu/1 tanu - sinu/1 cotu = cosu-sinu
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    Ranya Posts: 3, Reputation: 1
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    #4

    Nov 15, 2010, 06:29 AM
    cosu/1+tanu - sinu/1+cotu = cosu-sinu
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #5

    Nov 15, 2010, 02:08 PM

    Hint: first step is to replace the cotu and tanu functions with their sine and cosine equivalents.
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