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-   -   (1 cosu)/(1-cosu) - (1-cosu)/(1 cosu) = 4cotucscu (https://www.askmehelpdesk.com/showthread.php?t=525974)

  • Nov 14, 2010, 09:51 PM
    Ranya
    (1 cosu)/(1-cosu) - (1-cosu)/(1 cosu) = 4cotucscu
  • Nov 14, 2010, 10:58 PM
    Unknown008

    1. Combine the two fractions on the left hand side.
    2. Use the difference of two squares; , on the denominator.
    3. Expand the numerator.
    4. Simplify.

    You should get there fast enough.
  • Nov 15, 2010, 06:28 AM
    Ranya
    cosu/1 tanu - sinu/1 cotu = cosu-sinu
  • Nov 15, 2010, 06:29 AM
    Ranya
    cosu/1+tanu - sinu/1+cotu = cosu-sinu
  • Nov 15, 2010, 02:08 PM
    ebaines

    Hint: first step is to replace the cotu and tanu functions with their sine and cosine equivalents.

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