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    blair.1969's Avatar
    blair.1969 Posts: 2, Reputation: 1
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    #1

    Oct 10, 2010, 09:12 AM
    proving trigonometric identities..
    1. Cotx cosx = cscx - sinx
    2. (tanx - sinx)^2 + (1 - cosx) = (1 - secx)^2
    3. cotx + tanx = cscx^2+ sec^2 x/ cscx secx
    4. 1 - 2 cos^2x / cotx cosx = tanx - cotx
    5. sin^4x - cos^4x = sin^2x - cos^2x
    6. sin^6x + cos^6 = 1 - 3 sin^2x cos^2x
    7. cscx/cscx-1 + cscx/ cscx + 1 = 2sec^2x

    please help
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Oct 10, 2010, 09:53 AM

    That's just too much. You need to show us what you tried so far.

    A hint for any trig proof, convert everything to cos and sin if possible. Also, you might find it easier to go from several terms to single terms. For the first one as example, you would be easier off starting from (csc x - sin x).
    blair.1969's Avatar
    blair.1969 Posts: 2, Reputation: 1
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    #3

    Oct 10, 2010, 10:04 AM
    ex.
    tan^2x - sin^2x = tan^2x sin^2x
    proof:
    =tan^2x - sin^2x
    = (sin^2x/cos^2x) - sin^2x
    = (sin^2x - c0s^2x sin^2x)/ cos^2x
    =(sin^2x (1 - cos^2x))/ cos^2x
    = (sin^2x/cos^2x)(1-cos^2x)
    = tan^2x sin^2x
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Oct 10, 2010, 10:12 AM

    Right! :)
    paulini's Avatar
    paulini Posts: 1, Reputation: 1
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    #5

    May 3, 2011, 02:49 PM
    prove by identity cosx+cosxtan^2x=secx
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #6

    May 3, 2011, 04:57 PM
    Quote Originally Posted by paulini View Post
    prove by identity cosx+cosxtan^2x=secx
    Do as Unk suggested in his earlier post - convert tan^2x to sin^2x/cos^2x and go from there.

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