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-   -   Proving trigonometric identities.. (https://www.askmehelpdesk.com/showthread.php?t=515325)

  • Oct 10, 2010, 09:12 AM
    blair.1969
    proving trigonometric identities..
    1. Cotx cosx = cscx - sinx
    2. (tanx - sinx)^2 + (1 - cosx) = (1 - secx)^2
    3. cotx + tanx = cscx^2+ sec^2 x/ cscx secx
    4. 1 - 2 cos^2x / cotx cosx = tanx - cotx
    5. sin^4x - cos^4x = sin^2x - cos^2x
    6. sin^6x + cos^6 = 1 - 3 sin^2x cos^2x
    7. cscx/cscx-1 + cscx/ cscx + 1 = 2sec^2x

    please help
  • Oct 10, 2010, 09:53 AM
    Unknown008

    That's just too much. You need to show us what you tried so far.

    A hint for any trig proof, convert everything to cos and sin if possible. Also, you might find it easier to go from several terms to single terms. For the first one as example, you would be easier off starting from (csc x - sin x).
  • Oct 10, 2010, 10:04 AM
    blair.1969
    ex.
    tan^2x - sin^2x = tan^2x sin^2x
    proof:
    =tan^2x - sin^2x
    = (sin^2x/cos^2x) - sin^2x
    = (sin^2x - c0s^2x sin^2x)/ cos^2x
    =(sin^2x (1 - cos^2x))/ cos^2x
    = (sin^2x/cos^2x)(1-cos^2x)
    = tan^2x sin^2x
  • Oct 10, 2010, 10:12 AM
    Unknown008

    Right! :)
  • May 3, 2011, 02:49 PM
    paulini
    prove by identity cosx+cosxtan^2x=secx
  • May 3, 2011, 04:57 PM
    ebaines
    Quote:

    Originally Posted by paulini View Post
    prove by identity cosx+cosxtan^2x=secx

    Do as Unk suggested in his earlier post - convert tan^2x to sin^2x/cos^2x and go from there.

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