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    aqualizzie's Avatar
    aqualizzie Posts: 1, Reputation: 1
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    #1

    Sep 26, 2010, 05:31 PM
    How do you find the intercepts for x=-5?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Sep 26, 2010, 11:39 PM

    One of the simplest ways is to draw the graph and manually the intercept.

    Another way is to set in turn x = 0 and y = 0.

    Using x = 0, we get 0 = -5. Since that is not true, there is no intercept.
    Using y = 0, we get x = -5. That's your intercept and has coordinates (-5, 0)
    marydevos's Avatar
    marydevos Posts: 2, Reputation: 1
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    #3

    Oct 6, 2010, 04:28 PM
    x and y intercepts of the line y+3=16(x-2)
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    marydevos Posts: 2, Reputation: 1
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    #4

    Oct 6, 2010, 04:33 PM
    Comment on marydevos's post
    the answer in the back of books has the x is (35/16,0) y is (9,-35)
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #5

    Oct 6, 2010, 10:09 PM

    In your equation, put y = 0 and solve for x to find the x-intercept. (The y coordinates is 0)

    Similarly, put x = 0 and solve for y to find the y-intercept. (The x-coordinates is 0)
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