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caddym31e · Oct 5, 2010, 07:40 PM

how to solve for q in the equation y=log(-log(1-q))

Unknown008 · Oct 6, 2010, 01:47 AM

$y = log(-log(1-q))$

Raise the terms with the base 10.

$10^y = 10^{log(-log(1-q))}$

Now, this cancels the first log.

$10^y = -log(1-q)$

Move the minus sign, to become the power of (1-q)

$10^y = log(1-q)^{-1}$

Take the base 10 again:

$10^{10^y} = 10^{log(1-q)^{-1}}$

This takes out the other log.

$10^{10^y} = (1-q)^{-1}$

Convert the right side to a fraction:

$10^{10^y} = \frac{1}{1-q}$

Can you finish it now? Post what you get! :)

ebaines · Oct 6, 2010, 05:57 AM

Please do not double post the same question in two different forums. See: https://www.askmehelpdesk.com/mathem...-q-513930.html

It is interesting though that Galactus and Unknown008 got the answer in two different forms - though they are eqiuvalent.

Unknown008 · Oct 6, 2010, 06:38 AM

Yup, I like removing negative signs as soon as possible ;)

I wonder how I missed the other thread :rolleyes:

Must be tired >_<