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caddym31e · Oct 5, 2010, 07:41 PM

galactus · Oct 6, 2010, 04:28 AM

Just as e complements ln, 10 complements log.

Normally, logs are base 10 unless otherwise indicated.

$y=log(-log(1-q))$

$-10^{y}=log(1-q)$

$10^{-10^{y}}=1-q$

$q=1-10^{-10^{y}}$

$q=1-(\frac{1}{10})^{10^{y}}$

ebaines · Oct 6, 2010, 05:58 AM

Please do not double post the same question in two different forums. See: https://www.askmehelpdesk.com/math-s...ms-513991.html

It is interesting though that Galactus and Unknown008 got the answer in two different forms - though they are eqiuvalent.