Ask Me Help Desk - How to solve for q in the equation y=log(-log(1-q))

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how to solve for q in the equation y=log(-log(1-q))

Just as e complements ln, 10 complements log.

Normally, logs are base 10 unless otherwise indicated.

$y=log(-log(1-q))$

$-10^{y}=log(1-q)$

$10^{-10^{y}}=1-q$

$q=1-10^{-10^{y}}$

$q=1-(\frac{1}{10})^{10^{y}}$

Please do not double post the same question in two different forums. See: https://www.askmehelpdesk.com/math-s...ms-513991.html

It is interesting though that Galactus and Unknown008 got the answer in two different forms - though they are eqiuvalent.

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