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Indy717 · Feb 21, 2010, 07:06 PM

find an equation in the form of y=mx+b. Through (3, -5), parallel to y=4

Unknown008 · Feb 22, 2010, 07:18 AM

Use the formula:

$\frac{y\ -\ y-coordinate}{x\ -\ x-coordinate} = m$

For example, if you had (2, 1) with gradient 1,

$\frac{y - 1}{x-2} = 1$

This gives:

$y-1 = x - 2$

$y = x -1$

which is in the form y = mx + c.

EDIT: Note that a line parallel to the x-axis has a gradient of 0, and that parallel to the y-axis has gradient infinity.

Post your answer! :)

Tordmor · Feb 22, 2010, 07:36 AM

The general form of the linear equation has two parameters: m and b. So you need two unrelated pieces of information to calculate them. Those are the parallel line and the given point.

1. the parallel line:
y = 4 can be rewritten as y = 0 * x + 4
parallel means: having the same m value. So read the m value from the above equation and replace m in the result equation with that value.

2. the given point
Next replace x and y with the respective values from the given point and resolve to b. Now you have m and b and can give the result equation.