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-   -   Find an equationin the form y=mx+b. Through (3,-5), parallel to y=4 (https://www.askmehelpdesk.com/showthread.php?t=449936)

  • Feb 21, 2010, 07:06 PM
    Indy717
    find an equationin the form y=mx+b. Through (3,-5), parallel to y=4
    find an equation in the form of y=mx+b. Through (3, -5), parallel to y=4
  • Feb 22, 2010, 07:18 AM
    Unknown008

    Use the formula:



    For example, if you had (2, 1) with gradient 1,



    This gives:





    which is in the form y = mx + c.

    EDIT: Note that a line parallel to the x-axis has a gradient of 0, and that parallel to the y-axis has gradient infinity.

    Post your answer! :)
  • Feb 22, 2010, 07:36 AM
    Tordmor

    The general form of the linear equation has two parameters: m and b. So you need two unrelated pieces of information to calculate them. Those are the parallel line and the given point.

    1. the parallel line:
    y = 4 can be rewritten as y = 0 * x + 4
    parallel means: having the same m value. So read the m value from the above equation and replace m in the result equation with that value.

    2. the given point
    Next replace x and y with the respective values from the given point and resolve to b. Now you have m and b and can give the result equation.

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