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    rocknnrebellion's Avatar
    rocknnrebellion Posts: 1, Reputation: 1
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    #1

    Jan 21, 2010, 06:23 PM
    solve cos2x-cos^2x-2sinx+3=0 in the interval [0, 2 pi]
    solve cos2x-cos^2x-2sinx+3=0 in the interval [0, 2 pi]
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    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Jan 22, 2010, 06:35 AM

    Hint: use a couple of the usual trig identities to get everything in terms of sin(x). For example:



    Then you can solve for sin(x).
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