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leonardo1841 · Nov 14, 2009, 10:38 AM

There is also another formula which is confusing

Make e the subject

T = (1 + e/1 – e) x √L/10

Unknown008 · Nov 14, 2009, 09:58 PM

$T = \frac{1+e}{1-e}\ \times \ \frac{\sqrt{L}}{10}$

Is that it?

leonardo1841 · Nov 15, 2009, 04:03 AM

Sorry, I mistyped it there is meant to be a 5 instead of a 10, and the square root is over the whole of L/5

Unknown008 · Nov 15, 2009, 06:05 AM

Ok, so;

$T = \frac{1+e}{1-e} \times \sqrt{\frac{L}{5}}$

Multiply by 1-e, on both sides:

$T(1-e) = \frac{1+e}{\cancel{1-e}} \times \sqrt{\frac{L}{5}} \times \cancel{(1-e)}$

Expand both sides:

$T-eT = \sqrt{\frac{L}{5}} +e\sqrt{\frac{L}{5}}$

Bring all the 'e' on one side:

$T\cancel{-eT + eT} - \sqrt{\frac{L}{5}} = \cancel{\sqrt{\frac{L}{5}}} +e\sqrt{\frac{L}{5}}+ eT\cancel{ - \sqrt{\frac{L}{5}}}$

$T- \sqrt{\frac{L}{5}} = e\sqrt{\frac{L}{5}}+ eT$

Then factorise e;

$T - \sqrt{\frac{L}{5}} =e(\sqrt{\frac{L}{5}}+ T)$

It's nearly finished, can you take it now? :)

I hope it helped! :)