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mkd009 · Sep 7, 2009, 09:14 AM

what are the x and y intercepts of (-4,5) and (6,0)

what are the x and y intercepts of (3,7) and (-1,-5)

Unknown008 · Sep 7, 2009, 09:24 AM

Work the equations of the line joining the points concerned.

To do that, find the gradient between the two points, and use the formula for getting the equation of that line;

$Gradient = \frac{y_2 - y_1}{x_2-x_1}$

$\frac{y-y_{coordinate}}{x-x_{coordinate}}= Gradient$

Then, put x = 0 to have the y intercept, and y=0 to have the x intercept.

I'll do the first one.

(-4, 5) and (6, 0)

Let (-4, 5) be (x1, y1) and (6, 0) be (x2, y2)

$Gradient = \frac{y_2 - y_1}{x_2-x_1} = \frac{0 - 5}{6-(-4)} = \frac{-5}{10} = -\frac12$

Now, the formula to have the equation;

here, you choose any of the two points;

$\frac{y-y_{coordinate}}{x-x_{coordinate}}= Gradient$

$\frac{y-0}{x-6}= -\frac12$

$y= -\frac12 (x-6)$

Now, I put x = 0 to have the y interept;

$y= -\frac12 ((0)-6)$

$y= 3$

Putting y=0,

$(0)= -\frac12 (x-6)$

$0= (x-6)$

$x= 6$

Now, try the second one.