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    tejas1234567's Avatar
    tejas1234567 Posts: 1, Reputation: 1
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    #1

    Aug 25, 2009, 06:58 AM
    proof of circle
    draw a circle.
    draw any cyclic quadrilateral in it.
    name it A-B-C-D.
    join BD and AC (diagonals)


    PROVE THAT:
    AC x BD= AB x CD + BC x AD
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Aug 25, 2009, 07:45 AM

    I think the easiest way to tackle this problem is taking the sides AB, BC, CD and DA to be equal. You therefore take a square. The length of the diagonal is always times the side of the square, from Pythagoras' Theorem. Then, using your drawing, let x be the length of the side of your square the diagonal will be and use those to show the proof.
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