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veron · Mar 23, 2009, 10:45 AM

A ship sailed from Port K to Port L. Port L is located 28km East and 16km South of Port K.
Calculate the distance of KL and the bearing of Port L from Port K.
Give answer correct to 3 significant figures.

Perito · Mar 23, 2009, 10:48 AM

This requires only the Pythagorean Theorem:

$R^2 = X^2 + Y^2$

where X and Y are the two sides of the right triangle and R is the side opposite the 90 degree angle.

galactus · Mar 23, 2009, 11:16 AM

Also, the bearing can easily be calculated from the two given distances.

Per the diagram:

$@=tan^{-1}(\frac{16}{28})$

Do you want a bearing or an azimuth? There is a difference.

An azimuth is an angle turned clockwise off due north. For that, just add the answer from above to 90 degrees.

A bearing is done in quadrants, as in land deeds.

Your bearing would be $S[90-(\text{the above answer})]E$

ebaines · Mar 23, 2009, 11:18 AM

The bearing from Port K to L can be calculated from arctan(16/28) - this is the angle south of east, so add 90 degres to get a bearing from north.

dug2pak · Sep 1, 2009, 02:15 AM

Pythagorean Theorem...

The hypotenuse is equivalent to the square root of the sum of the square of both sides.

abuanremedios · Jan 11, 2010, 02:04 AM

What is the difference between north 60 degree from 60 dergee northeast

abuanremedios · Jan 11, 2010, 02:05 AM

Originally Posted by abuanremedios

what is the difference between north 60 degree from 60 dergee northeast

:)