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    veron's Avatar
    veron Posts: 1, Reputation: 1
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    #1

    Mar 23, 2009, 10:45 AM
    Trigonometry bearings
    A ship sailed from Port K to Port L. Port L is located 28km East and 16km South of Port K.
    Calculate the distance of KL and the bearing of Port L from Port K.
    Give answer correct to 3 significant figures.
    Perito's Avatar
    Perito Posts: 3,139, Reputation: 150
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    #2

    Mar 23, 2009, 10:48 AM

    This requires only the Pythagorean Theorem:



    where X and Y are the two sides of the right triangle and R is the side opposite the 90 degree angle.
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #3

    Mar 23, 2009, 11:16 AM
    Also, the bearing can easily be calculated from the two given distances.

    Per the diagram:



    Do you want a bearing or an azimuth? There is a difference.

    An azimuth is an angle turned clockwise off due north. For that, just add the answer from above to 90 degrees.

    A bearing is done in quadrants, as in land deeds.

    Your bearing would be
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    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #4

    Mar 23, 2009, 11:18 AM

    The bearing from Port K to L can be calculated from arctan(16/28) - this is the angle south of east, so add 90 degres to get a bearing from north.
    dug2pak's Avatar
    dug2pak Posts: 2, Reputation: 1
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    #5

    Sep 1, 2009, 02:15 AM
    Pythagorean Theorem...

    The hypotenuse is equivalent to the square root of the sum of the square of both sides.
    abuanremedios's Avatar
    abuanremedios Posts: 2, Reputation: 1
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    #6

    Jan 11, 2010, 02:04 AM
    What is the difference between north 60 degree from 60 dergee northeast
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    abuanremedios Posts: 2, Reputation: 1
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    #7

    Jan 11, 2010, 02:05 AM
    Quote Originally Posted by abuanremedios View Post
    what is the difference between north 60 degree from 60 dergee northeast

    :)

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