 |
|
| Browse | Ask | Answer | Search | Join/Login |
|
|
||||
|
Trigonometry and bearings
Captain Jack Sparrow is looking for Davey Jones" chest. The Black Pearl leaves port at 10 am and travels due east at 25 knots. At 11:25 am Jack Sparrow changes the ship's course to S 23 degrees E and travels at 36 knots until 1:18 pm. Then the ship travels due east at 52 knots until 3:25 pm. Finally Jack Sparrow changes course to N 16 degrees E and travels at a speed of 61 knots until 6 pm when he locates the treasure. Find the distance the Black Pearl is from port when the treasure is located and the bearing from treasure back to port.
|
||||
|
|
|
||||
|
|
||||
|
|
| Question Tools | Search this Question |
Check out some similar questions!
An aeroplane flies 120km on a bearing of 130 degrees. It then alters course and flies 250km on a bearing of 035 degrees. a) How far east is the plane from its starting point? b) How far north is the plane from its starting point? c) How far is the plane from its starting point? :confused:
A boat sails form port on a bearing of 290 degrees for 130 nm. How far north is it form its starting point?
A plane is 150 miles north and 100 miles east of an airport. What bearings should be taken to fly directly to the airport?
I previously asked about this, so I'll now give an example of what I was asking The question is :- A ship sails on a bearing of 120 degrees for 50 km, How far east has it traveled? They book I'm using shows a typical diagram for the situation, however it then draws a right angle triangle...
Can you please tell me what does it mean when it says:- 'The difficulty with trigonometric problems involving bearings is dealing with those angles greater than 90 degrees whose trigonometric ratios have negative values. To avoid this we have to find a right- angled triangle that we can readily...
View more questions Search
|
