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    pices1970's Avatar
    pices1970 Posts: 1, Reputation: 1
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    #1

    Feb 6, 2009, 05:26 PM
    Algebra specifics
    (-3y-1) – (6y-4) – (y+4)
    KISS's Avatar
    KISS Posts: 12,510, Reputation: 839
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    #2

    Feb 6, 2009, 06:17 PM

    I'm going to tell you to do it the easy way, not the stupid way;

    You have y's and constants

    Count them at the same time paying attention to sign changes.

    This problem is:

    (-3y-1) + (-1)(6y-4)+(-1) (y+4)

    Now count the y's and constants and eventually add

    y: -3, -6, -1

    Constants: -1, 4, -4

    Add the y's
    -10y

    Add constants

    -1

    -1-10y

    Done, and simeple. Bet it's not the way you were taught?

    The way you were taught, if I'm correct, is too error prone.

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