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    dragosani's Avatar
    dragosani Posts: 6, Reputation: 1
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    #1

    Feb 3, 2009, 01:27 PM
    physics motion in two dimensions
    A bomber flying in level flight at 200 m/s drops a 500kg bomb from an altitude of 3000m. a. find the horizontal and vertical components of the velocity and B.how far has it travelled horizontally after release when it strikes.

    I know you're given :
    V: 200m/s
    y: 3000m
    a: -9.8m/s^2

    I've tried everything but I can't figure out how to break it down into x and y components if I'm not given an angle. Any help is appreciated.
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Feb 3, 2009, 01:41 PM

    Treat the horizontal and vertical components independently. For the vertical, you know the bomb drops with no initial vertical velocity component and with an acceleration of -9.8 m/s^2. So from a height of 3000m you can calculate the time it takes to hit the ground. Call this time T. For the horizontal, given no air friction, the bomb moves at a constant 200 m/s horizontally with no deceleration, so you can calculat how far it moves in the horizontal direction during time T.

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