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    bosayna's Avatar
    bosayna Posts: 1, Reputation: 1
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    #1

    Dec 13, 2008, 07:29 AM
    quadratic equations
    A circular magnet has an inner radius x cm, an outer radius 2 cm larger and its depth is the same as the inner radius (as shown).
    If the total volume of the magnet is 120 pi cm^3, find x
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #2

    Dec 13, 2008, 10:40 AM

    Start by writing an equation for the volume, then equate it to 120pi and then solve.
    Credendovidis's Avatar
    Credendovidis Posts: 1,593, Reputation: 66
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    #3

    Dec 14, 2008, 07:10 AM
    Quote Originally Posted by bosayna
    A circular magnet has an inner radius x cm, an outer radius 2 cm larger and its depth is the same as the inner radius (as shown).
    If the total volume of the magnet is 120 pi cm^3, find x
    Not clearly stated ( as there is no drawing shown as suggested) is if this is a magnet of x cm radius magnetic material with a coating of 2 cm non-magnetic material, or a magnet without an innercore of x cm radius. I assume the latter.

    In that case just calculate the volume of a cylinder with a radius of x + 2 cm and a depth of x cm, and the volume of another cylinder with a radius of x cm and a depth of x cm, and deduct the smaller volume from the bigger one. The resulting value is equal to the given 120 pi cm^3 value.

    From this you can solve x.

    Success !

    :)
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