how do you do this problem?

what are the x-intercepts for y=x(squared) - 25?

to find the x-intercepts, set the equation equal to zero. (sub 0 in for y, then solve for x)

y=x^2 - 25

X-Intercept means that the point that lies on X-Axis and on X-axis Y=0 for all values of X so to find X-Intercept, just replace Y by Zero in your equation

0=x^2-25
0={(x)^2}-(5^2)
we know that x^2 - y^2 = (X+y) (x-y)

so,
0=(x+5) (x-5)
equating both to zero
x+5=0 , x-5=0
x=-5 , x=5

so your X-intercepts are

(-5,0) and (5,0)


hope it answers the question

the x intercepts are 5, -5

the x intercepts are 5,-5