Half of Henry's age added to 1/3 of Daisy's age is 11 years. Six years from now, the sum of their ages will be 40 years. How old is each?

Let Henry's age be h and Daisy's age be d.

Half of Henry's age; h/2
added to Daisy's age; h/2 + d
is 11 years; h/2 + d = 11

Six years from now, Henry will be h+6 years
Daisy will be d + 6 years.
The sum of their ages will be 40; (h+6) + (d + 6) = 40

You have two equations with two unknowns. Can you get the answer?

And post it here? :)