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-   -   Net Force with aircraft. (https://www.askmehelpdesk.com/showthread.php?t=509181)

  • Sep 20, 2010, 08:14 AM
    tristan2010
    Net Force with aircraft.
    An Airplane weighing 12000N is in a 30deg bank turn. The wings are producing 12000N of lift.
    Compute the net forces along the vertical and horizon axis.
    Compute vertical and horizontal accelerations
  • Sep 20, 2010, 08:19 AM
    Unknown008

    Have a quick sketch of what is happening to your airplane. Break down the forces into components parallel and perpendicular to the vertical and you'll get the net force by adding/subtracting the vectors, and from there, you can use F=ma to find the acceleration.

    Post what you get! :)
  • Sep 20, 2010, 08:38 AM
    Unknown008

    EDIT: Sorry, didn't see your picture. Could you try avoiding using the comment button please and use the answer this question box? Thanks. I'm looking at what you've done now...
  • Sep 20, 2010, 08:41 AM
    tristan2010
    Comment on Unknown008's post
    I don't know what to do from there. By getting the 6000N and 10392N I found vertical and horizontal components of lift... After that Im clueless =/
  • Sep 20, 2010, 08:51 AM
    Unknown008

    Ok, here's how I see the airplane:

    http://p1cture.me/images/81262331180011504127.png

    The force is perpendicular to the wings, not along them. If the plane was horizontal, the lift should be vertical to allow it to rise.

    Can you try it again?
  • Sep 20, 2010, 08:59 AM
    tristan2010
    Comment on Unknown008's post
    Aha, mas mixing up two separate images I made, and good catch =]This would mean that my earlier note of vertic. And horiz. Components of lift are backwards, right?
  • Sep 20, 2010, 09:07 AM
    Unknown008

    Backwards? What do you mean by that? :confused:

    Anyway, here's the vertical component:





    Can now find the mass of the airplane, and get the acceleration? :)

    And last thing, could you use the answer box instead of the comment button please? Thanks :)
  • Sep 20, 2010, 09:15 AM
    tristan2010
    The mass would be1224.5. But I just found mass by W=MG. I don't see how that fits in.
  • Sep 20, 2010, 09:26 AM
    Unknown008

    Yes, that's it :)

    It's weight is 12000 N, so, it's mass is 12000/9.8 = 1224.5 kg

    Now, use F = ma to get the acceleration in the direction of the resultant vectors.

    You have one horizontal acceleration, and one vertical acceleration. Use the resultant force you got in (a).
  • Sep 20, 2010, 09:29 AM
    tristan2010
    Comment on Unknown008's post
    Would the mass be opposite to the 12000N of lift?
  • Sep 20, 2010, 09:30 AM
    tristan2010
    Would the mass be opposite to the 12000N of lift?
  • Sep 20, 2010, 09:34 AM
    tristan2010
    Comment on tristan2010's post
    And what does that have to do with the net force along the vertical and horizontal axis?
  • Sep 20, 2010, 09:34 AM
    Unknown008

    The mass is a scalar quantity and is not 'opposite' of anything (or I'm not understanding what you are saying here... )

    The force on the horizontal is 6000 N, the mass of the plane is 1224.5 kg.

    So,

    6000 N = (1224.5 kg)(a)

    Find the value of a, the horizontal acceleration of the plane.

    Then, use the same formula for the vertical acceleration. :)
  • Sep 20, 2010, 09:43 AM
    tristan2010
    Thanks for all your help and patience =].
  • Sep 20, 2010, 10:00 AM
    Unknown008

    You're welcome :)

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