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-   -   Quadratic equation involving speed (https://www.askmehelpdesk.com/showthread.php?t=446413)

  • Feb 12, 2010, 06:47 PM
    HuiLi
    Quadratic equation involving speed
    Adrain and Bala decided to go on a cycling expedition.Both of them chose different routes to the destination.Adrain travelled by rooute A,which is 120km long,at an average speed of xkm/h.Bala chose route B,which is 5km shorter,but has more challenging terrain.He covered the distance at an average speed of 2km/h slower than Adrain.
    Qn:Given that Bala arrived at the destination 40 minutes later than Adrain,form an equation in x.


    I'm really bad at maths,especially speed problems,anyone can help me out?
  • Feb 13, 2010, 11:06 AM
    galactus

    Since x is Adrian's rate, then Bala's rate is x-2.

    The time Adrian made it is t, then Bala made it in t+2/3 hours.

    d=rt

    Adrian: 120=xt

    Bala:

    Solve for x
  • Feb 14, 2010, 12:14 AM
    HuiLi

    Bala:115=(x-2)(120/x+2/3)
    =(360+2x)/3x
    Is it = (360x-720+2xsquare-4x)/(3xsquare-6x) ?

    I'm not sure because from here on the answer is different from the one given.
  • Feb 14, 2010, 12:35 AM
    HuiLi

    The answer I get is 343xsquare-1046x-720=0
    while the correct answer is 2xsquare+11x-720=0
  • Feb 14, 2010, 04:21 AM
    galactus

    Try again then. Because it comes out to

    Multiply through by the LCM, which is

    3x(x-2) and cancel terms accordingly.
  • Feb 14, 2010, 08:42 PM
    HuiLi

    Here's how I do it:
    115=(x-2)(120/x+2/3)
    120/x + 2/3 = 360+2x/3x
    (360+2x/3x)(x-2)
    =(354x-720+2xsquare)/(3xsquare-6xsquare)

    115/1 = (354xsquare-720+2xsquare)/(3xsquare-6x)

    115(3xsquare-6x)=(354xsquare-720+2xsquare)

    345xsquare-690x-354xsquare-720-2xsquare=0

    -11xsquare-690x-720=0

    I had done it about 3 times,but the answer I get is still this.I checked but I think all the steps I had done are correct?
  • Feb 14, 2010, 09:38 PM
    morgaine300
    Quote:

    Here's how I do it:
    115=(x-2)(120/x+2/3)
    120/x + 2/3 = 360+2x/3x
    (360+2x/3x)(x-2)
    This whole thing isn't working. When you multiplied the 3x by the (120/x + 2/3), the 3 cancels out on the second term and the x doesn't end up in the denominator:



    Or, so you can visualize it more easily:



    On the left term the x cancels, which you did correctly. But on the right, the 3's cancel so that denominator disappears, and the x goes in the numerator:



    You also missed the extra (x - 2). If you're multiplying through by (3x)(x-2) then you've got that extra (x-2) in there as well. You've only used the 3x. (I think - honestly I'm having a hard time following what you're doing.)

    Try to fix those and go from there.

    I did it a different way, which for me was a heck of a lot easier, not to mention easier for my mind to think up. I can't say as I understand the LCD in that situation, other than I got it to work out to the same thing by doing it.

    I FOILed the right side first, and then multiplied both sides by 3x.

    Oh, and used a ^ (carrot) for exponents, like 2x^2 + 7.
  • Feb 16, 2010, 03:53 AM
    HuiLi

    I think I get it!! :D
    115/(x-2)-120/x=2/3

    115x-120x+240/x(x-2)=2/3

    2xsquare-4x=3(115-120x+240)

    345x-360x+720-2xsquare+4x

    -11x+720-2xsquare

    2xsquare+11x-720

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