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    HuiLi's Avatar
    HuiLi Posts: 17, Reputation: 1
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    #1

    Feb 12, 2010, 06:47 PM
    Quadratic equation involving speed
    Adrain and Bala decided to go on a cycling expedition.Both of them chose different routes to the destination.Adrain travelled by rooute A,which is 120km long,at an average speed of xkm/h.Bala chose route B,which is 5km shorter,but has more challenging terrain.He covered the distance at an average speed of 2km/h slower than Adrain.
    Qn:Given that Bala arrived at the destination 40 minutes later than Adrain,form an equation in x.


    I'm really bad at maths,especially speed problems,anyone can help me out?
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #2

    Feb 13, 2010, 11:06 AM

    Since x is Adrian's rate, then Bala's rate is x-2.

    The time Adrian made it is t, then Bala made it in t+2/3 hours.

    d=rt

    Adrian: 120=xt

    Bala:

    Solve for x
    HuiLi's Avatar
    HuiLi Posts: 17, Reputation: 1
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    #3

    Feb 14, 2010, 12:14 AM

    Bala:115=(x-2)(120/x+2/3)
    =(360+2x)/3x
    Is it = (360x-720+2xsquare-4x)/(3xsquare-6x) ?

    I'm not sure because from here on the answer is different from the one given.
    HuiLi's Avatar
    HuiLi Posts: 17, Reputation: 1
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    #4

    Feb 14, 2010, 12:35 AM

    The answer I get is 343xsquare-1046x-720=0
    while the correct answer is 2xsquare+11x-720=0
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #5

    Feb 14, 2010, 04:21 AM

    Try again then. Because it comes out to

    Multiply through by the LCM, which is

    3x(x-2) and cancel terms accordingly.
    HuiLi's Avatar
    HuiLi Posts: 17, Reputation: 1
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    #6

    Feb 14, 2010, 08:42 PM

    Here's how I do it:
    115=(x-2)(120/x+2/3)
    120/x + 2/3 = 360+2x/3x
    (360+2x/3x)(x-2)
    =(354x-720+2xsquare)/(3xsquare-6xsquare)

    115/1 = (354xsquare-720+2xsquare)/(3xsquare-6x)

    115(3xsquare-6x)=(354xsquare-720+2xsquare)

    345xsquare-690x-354xsquare-720-2xsquare=0

    -11xsquare-690x-720=0

    I had done it about 3 times,but the answer I get is still this.I checked but I think all the steps I had done are correct?
    morgaine300's Avatar
    morgaine300 Posts: 6,561, Reputation: 276
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    #7

    Feb 14, 2010, 09:38 PM
    Here's how I do it:
    115=(x-2)(120/x+2/3)
    120/x + 2/3 = 360+2x/3x
    (360+2x/3x)(x-2)
    This whole thing isn't working. When you multiplied the 3x by the (120/x + 2/3), the 3 cancels out on the second term and the x doesn't end up in the denominator:



    Or, so you can visualize it more easily:



    On the left term the x cancels, which you did correctly. But on the right, the 3's cancel so that denominator disappears, and the x goes in the numerator:



    You also missed the extra (x - 2). If you're multiplying through by (3x)(x-2) then you've got that extra (x-2) in there as well. You've only used the 3x. (I think - honestly I'm having a hard time following what you're doing.)

    Try to fix those and go from there.

    I did it a different way, which for me was a heck of a lot easier, not to mention easier for my mind to think up. I can't say as I understand the LCD in that situation, other than I got it to work out to the same thing by doing it.

    I FOILed the right side first, and then multiplied both sides by 3x.

    Oh, and used a ^ (carrot) for exponents, like 2x^2 + 7.
    HuiLi's Avatar
    HuiLi Posts: 17, Reputation: 1
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    #8

    Feb 16, 2010, 03:53 AM

    I think I get it!! :D
    115/(x-2)-120/x=2/3

    115x-120x+240/x(x-2)=2/3

    2xsquare-4x=3(115-120x+240)

    345x-360x+720-2xsquare+4x

    -11x+720-2xsquare

    2xsquare+11x-720

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