[2(x+1)+6]=10

Distribute the 2 to get [2x+2+6]=10
Add the 2 and 6 to get 2x+8 = 10
Subtract the 8 to get 2x = 2
Divide by 2 to get x = 1

Quote:

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Originally Posted by josedelaluz

Distribute the 2 to get [2x+2+6]=10
Add the 2 and 6 to get 2x+8 = 10
Subtract the 8 to get 2x = 2
Divide by 2 to get x = 1

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And also -9

What do you mean by and -9

Quote:

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Originally Posted by josedelaluz

What do you mean by and -9

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we are solve inequality involving absolute value
the answer is -9 or 1

Ok so the [ ] are absolute values,
The first solution shows the positive value. The other one would be to write
-2(x+1)-6 = 10 The inside is worth the opposite values, 2 becomes -2 and 6 is -6
-2x - 2 -6 = 10 Distribute the -2
-2x -8 = 10 Add the -2 and -6
-2x = 18 Add the 8
x = -2 Divide by -2

Lol, It think you missed the last line josedelaluz..

Ok, here's what you get;

-2x=18

then

x=-9

Btw josedelaluz, where did you get that 'x = -2'?

Quote:

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Originally Posted by Unknown008

Lol, It think you missed the last line josedelaluz..

Ok, here's what you get;

-2x=18

then

x=-9

Btw josedelaluz, where did you get that 'x = -2'?

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Think you

Quote:

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Originally Posted by Unknown008

Lol, It think you missed the last line josedelaluz..

Ok, here's what you get;

-2x=18

then

x=-9

Btw josedelaluz, where did you get that 'x = -2'?

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Not sure, meant to type x = -9,

Quote:

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Originally Posted by josedelaluz

Not sure, meant to type x = -9,

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Its right that what I have. I just did not know how I get it.

Quote:

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Originally Posted by karen1231

its right that what i have. i just did not know how i get it.

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What you can do is;

|2(x+1)+6| = 10

That's the same as 2(x+1)+6 = |10|

Then, you'll have two equations;

2(x+1)+6 = +10 and 2(x+1)+6 = -10

Now, you can get the answer more easily