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    IcantfigureoutMATH's Avatar
    IcantfigureoutMATH Posts: 2, Reputation: 1
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    #1

    May 31, 2007, 03:35 PM
    Any ideas on functions?
    Use f(x) = 7x^3-9 and g(x)=1/13x to evaluate/simplify the following. 1/7(f(3*square root x) + 9

    Am I suppose to take the cubed root of 7x^3-9?
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    ebaines Posts: 12,131, Reputation: 1307
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    #2

    May 31, 2007, 04:07 PM
    Quote Originally Posted by IcantfigureoutMATH
    Use f(x) = 7x^3-9 and g(x)=1/13x to evaluate/simplify the following. 1/7(f(3*square root x) + 9

    Am I suppose to take the cubed root of 7x^3-9?
    It would help if you could be a little clearer with these functions - please use parentheses:

    Is g(x) = 1/(13x), or is it (1/13)x?
    Is the expression you're trying to evaluate (1/7)(f(3*root(x)+9)), or is it 1/(7*f(3 root(x))) + 9, or is it something else?
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    IcantfigureoutMATH Posts: 2, Reputation: 1
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    #3

    May 31, 2007, 04:31 PM
    Quote Originally Posted by ebaines
    It would help if you could be a little clearer with these functions - please use parentheses:

    Is g(x) = 1/(13x), or is it (1/13)x?
    Is the expression you're trying to evaluate (1/7)(f(3*root(x)+9)), or is it 1/(7*f(3 root(x))) + 9, or is it something else?
    OH sorry I was typing looking at something else...

    g(x)=(1/13)x to evaluate/simplify the following.

    Expression is as follows: (1/7)(f(3*square root x) + 9

    Thanks.
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    ebaines Posts: 12,131, Reputation: 1307
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    #4

    May 31, 2007, 05:57 PM
    OK, I now get the g(x) function, But your parentheses in the subsequent function still don't match up - please correct.
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