[nccaitlin91]

Ok so I have another logarithmic derivative equation

y= ln (3x/tan x)

Normally I would do

y1= ln 3x-ln tanx

but i am thinking since there are trig functions, it has to be set up differently. Problems in the book are not helping me answer this problem.

[ebaines]

I'm not sure what yuo mean by the term "y1" - please clarify. Do you mean deribcvitive of y?

It is true that if ln(a/b) = ln(a) - ln(b), so if y(x)= ln(3x/tanx) then y(x) = ln(3x) - ln(tanx). But now you must find the derivatives of both of these terms.