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    meharihaile's Avatar
    meharihaile Posts: 6, Reputation: 1
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    #1

    Mar 1, 2015, 02:31 PM
    A scientist measures the standard enthalpy change for the following reaction to be -8
    A scientist measures the standard enthalpy change for the following reaction to be -888.2 kJ :

    2NH3(g) + 3 N2O(g)4N2(g) + 3 H2O(g)

    Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of N2O(g) is
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    meharihaile Posts: 6, Reputation: 1
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    #2

    Mar 1, 2015, 02:34 PM
    A scientist measures the standard enthalpy change for the following reaction to be -5
    Ca(OH)2(aq) + 2 HCl(aq)CaCl2(s) + 2 H2O(l)

    Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(l) is
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    meharihaile Posts: 6, Reputation: 1
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    #3

    Mar 1, 2015, 02:37 PM
    A scientist measures the standard enthalpy change for the following reaction to be
    A scientist measures the standard enthalpy change for the following reaction to be -51.0 kJ:

    Ca(OH)2(aq) + 2 HCl(aq)CaCl2(s) + 2 H2O(l)

    Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(l) is
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    meharihaile Posts: 6, Reputation: 1
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    #4

    Mar 1, 2015, 02:38 PM
    A scientist measures the standard enthalpy change for the following reaction to be
    A scientist measures the standard enthalpy change for the following reaction to be 154.4 kJ :

    CaCO3(s)CaO(s) + CO2(g)

    Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of CaO(s) is
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    #5

    Mar 1, 2015, 02:41 PM
    Chemistry
    A scientist measures the standard enthalpy change for the following reaction to be 154.4 kJ :
    CaCO3(s)    CaO(s) + CO2(g)

    Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of CaO(s) is
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    Curlyben Posts: 18,514, Reputation: 1860
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    Mar 1, 2015, 02:43 PM
    There's no need to spam the site.

    What do YOU think ?
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    Show us what you have done and where you are having problems..
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    meharihaile Posts: 6, Reputation: 1
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    #7

    Mar 1, 2015, 02:48 PM
    Quote Originally Posted by Curlyben View Post
    There's no need to spam the site.

    What do YOU think ?
    While we're happy to HELP we wont do all the work for you.
    Show us what you have done and where you are having problems..
    [IMG]file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gif[/IMG]H°rxn = (2 mol)[IMG]file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gif[/IMG]H°f(CO2(g)) + (1 mol)[IMG]file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gif[/IMG]H°H°f(N2(g))(N2(g)) - [(2 mol)[IMG]file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gif[/IMG]H°f(CO(g)) + (2 mol)[IMG]file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gif[/IMG]H°H°f(NO(g))](NO(g))] = -780.8 kJ

    Solve for[IMG]file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gif[/IMG]H°f(CO2(g)) in the above equation:
    [IMG]file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gif[/IMG]H°f(CO2(g)) = [[IMG]file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gif[/IMG]H°rxn - (1 mol)[IMG]file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gif[/IMG]H°H°f(N2(g))(N2(g)) + (2 mol)[IMG]file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gif[/IMG]H°f(CO(g)) + (2 mol)[IMG]file:///C:\Users\Safron\AppData\Local\Temp\msohtmlclip1\01 \clip_image001.gif[/IMG]H°H°f(NO(g))](NO(g))] / (2 mol)

    = [(-780.8 kJ) - (1 mol)(0.0 kJ/mol) + (2 mol)(-110.5 kJ/mol) + (2 mol)(90.3 kJ/mol)]/(2 mol)
    = -410.6 kJ/mol
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