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Vapor pressure of water
(Q) 48l of dry N2 passes through 36g h20 at 300K , and this results in a water loss of 1.20 g . The v.p of water is?The sol says , that water loss is observed because of escape of water molecules with N2 gas . Then it says that water vapours occupy the volume of N2 i.e 48l , this part I am not able to understand , why would water occupy the same volume as that of N2 , it isn't mentioned that these 2 are in some container of vol 48 l , so what's the logic behind this , then the sol proceeds , by apllying pv=mrt/M .
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