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    oliviachin's Avatar
    oliviachin Posts: 4, Reputation: 1
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    #1

    Nov 14, 2013, 10:45 PM
    average velocity during the time interval
    The position of a particle moving along the x axis is given by zx=12+10t-3.0t^2 m , where t is in s. What is the average velocity during the time interval t = 1.0s to t = 3.0s?

    Is the answer -6.0m/s or -4.0m/s or -2.0m/s?

    I dofferentiate x to grt dx/dt = 10-6t , substitue the times, answer is 4 & -8. Total disppacement is -8-4 = -12. Time elapsed is 3 s? So -12/3 = -4m/s. Is this correct?
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    Nov 17, 2013, 12:40 PM
    Sorry, not right - it's actually easier than this. The average velocity = change in position divided by time. So determine the value of x(3) - x(1), and divide by time to get average velocity.
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