Ask Experts Questions for FREE Help !
Ask
    rjwjfw's Avatar
    rjwjfw Posts: 1, Reputation: 1
    New Member
     
    #1

    Nov 11, 2013, 05:57 PM
    How do I completely factor 8x^2 - 50
    I am trying to help my daughter with her Algebra homework but I forgot how to do this kind of problem: 8x squared - 50. She has to factor the problem completely.
    I factored out a 2 which left me with 2(4x^2 - 25) but what next?
    neodarwinian's Avatar
    neodarwinian Posts: 74, Reputation: 1
    Junior Member
     
    #2

    Nov 11, 2013, 07:38 PM
    That appears to be it.

    There are no further common factors that I can see.

    2(4X^2 - 25)
    ============This appears to be the fully factored expression. ( especially at the HS level )
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
    Expert
     
    #3

    Nov 12, 2013, 09:13 AM
    There is another step, recognizing that 4x^2-25 is the difference of two squares. Remember that:



    In this case setting a = 2x and b = 5 gives you:


    So the final answer is:


Not your question? Ask your question View similar questions

 

Question Tools Search this Question
Search this Question:

Advanced Search

Add your answer here.


Check out some similar questions!

Factor Trinominal Completely [ 0 Answers ]

x^2(y-8)-18(y-8)+80(y-8)

Factor completely 125 -27z^3? [ 5 Answers ]

I really need help with this problem and I know it is easy but I forgot how to factor completely 125 -27z^3. please help me!!

Factor Completely [ 4 Answers ]

3x^5 y^2 - 21x^2 y^7

Factor 4x^2 - 8x= completely [ 1 Answers ]

I need to know how to factor this problem completely because I have no idea of what Im doing here.

Factor Completely [ 3 Answers ]

how do I solve this problem Factor Completely 16x squared - 81y to the fourth


View more questions Search