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A converging lens has a focal length of 20.0 cm. Locate the image for object distances of (a) 40.0 cm, (b) 20.0 cm, and (c) 10.0 cm. For each case, state whether the image is real or virtual and upright or inverted. Find the magnification in each case.
A small object is located 30.6 cm in front of a concave mirror with a radius of curvature of 40.9 cm. So the question is Where will the image be formed? I thought I use this equation to solve 1/do + 1/di= 1/f I solved for R by using f=(1/2)R and got 20.45 I then plug that in with all my...
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