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    rayray820's Avatar
    rayray820 Posts: 3, Reputation: 1
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    #1

    Jan 3, 2013, 10:55 AM
    probability of having the winning ticket for a raffle
    If 200 tickets are sold to win 1 of 2 TV's. If I bought 1 ticket, what are my chances of winning 1 of the TV's
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Jan 3, 2013, 11:10 AM
    One way to approach this is like this: the probability of winning a TV is equal to the probabilty of (a) winning a TV with the first drawing, plus (b) the probability of losing the first drawing and winning the second.

    Another way to approach it is to consider that the probability of winning a TV is 1 minus the probability of not winning a TV. The probability of not winning a TV is equal to the probability of losing on both the first and second drawings.

    Both approaches give the same answer. I suggest that you try both and tell us what you get for an answer - we'll check it for you.
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    rayray820 Posts: 3, Reputation: 1
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    #3

    Jan 3, 2013, 11:16 AM
    Quote Originally Posted by ebaines View Post
    One way to approach this is like this: the probability of winning a TV is equal to the probabilty of (a) winning a TV with the first drawing, plus (b) the probability of losing the first drawing and winnig the second.

    Another way to approach it is to consider that the probability of winning a TV is 1 minus the probability of not winning a TV. The probability of not winning a TV is equal to the probability of losing on both the first and second drawings.

    Both approaches give the same answer. I suggest that you try both and tell us what you get for an answer - we'll check it for you.
    answer: Ok, that was a bit confusing, but I came up with this: the probabilty of winning one of the 2 TV's if 200 tickets were sold is 1% (2/200)= 0.01 X 100 = 1%
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #4

    Jan 3, 2013, 11:22 AM
    That's correct.
    rayray820's Avatar
    rayray820 Posts: 3, Reputation: 1
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    #5

    Jan 3, 2013, 11:35 AM
    Quote Originally Posted by ebaines View Post
    That's correct.
    Cool, thanks

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