Ask Experts Questions for FREE Help !
Ask
    austentic's Avatar
    austentic Posts: 1, Reputation: 1
    New Member
     
    #1

    Jun 11, 2012, 03:40 AM
    Simple Hess's Law question. Difference between kJ and kJ/mol
    I have a sheet on Hess's Law where Enthalpy change is sometimes given as kJ and other times kJ/mol.
    Why? What's the difference?

    The latter is given as "The heat of vaporisation of water is 44kJ/mol. Calculate the heat of reaction [gaseous ethanol]... "
    Why is it kJ/mol and should the heat of reaction be given as kJ or kJ/mol?
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
    Expert
     
    #2

    Jun 11, 2012, 08:00 AM
    Enthalpy is measured in kJ/mole. The heat of reaction may also be expressed in kJ/mole, but if you know how many moles of material are involved you can calculate the total heat released (or absorbed) by a reaction in kJ. Converesely, in a lab experiment you might measure the heat produced in kJ, and the calculate the enthalpy of the materials in terms of kJ/mole.

Not your question? Ask your question View similar questions

 

Question Tools Search this Question
Search this Question:

Advanced Search

Add your answer here.


Check out some similar questions!

Chemistry Hess's Law problem [ 2 Answers ]

"Water gas" is an industrial fuel composed of a mixture of carbon monoxide and hydrogen gases. When this fuel is burned, carbon dioxide and water forms as a result. From the information given below, write a balanced equation and determine the enthalpy of this reaction: CO(g) + ? 1/2 O2(g) ?...

What is the difference between law by statute and law by compliance. [ 1 Answers ]

In the case of Macaura vs Northern Assurance Company 1925, need to know how it was held.considering the results of incorporation. Thanks

Hess's Law (simple) [ 1 Answers ]

1) NaOH(s)--> Na+(aq) + OH- (aq) 2) Na+(aq) + OH(aq) + H+(aq) + Cl-(aq) --> H2O + Na+(aq) + Cl-(aq) Target equation: NaOH(s) + H+(aq) + Cl(aq)--> H20 + Na+(aq) + Cl-(aq) I need help solving this.. Thanks


View more questions Search