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    chemgirl109 Posts: 1, Reputation: 1
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    #1

    May 24, 2012, 06:29 PM
    Chemistry Acid/Base Titration
    A NaOH solution was standardized by titration with a sample of potassium hydrogen phthalate KHC8H4O4 (molar mass= 204.2 g/mol) A sample of pure potassium hydrogen phthalate weighing 3.918 grams was dissolved in water and titrated with the NaOH solution. To reach the equivalence point, 58.90 mL of base was required. (Note: the NaOH and the KHC8H4O4 react in a one to one ratio)



    a) How many moles of the solid acid were used in this reaction



    b) knowing the acid is monoprotic ( so it will react in a one to one ration with NaOH) how many moles of the base were used in this reaction



    c) what was the concentration of the basic solution
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    Ask4material Posts: 4, Reputation: 1
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    May 31, 2012, 03:33 AM
    a) no. of mole X molar mas = mass
    x204.2=3.918 find x

    b) x

    conc X vol = solute mass
    c) [conc](58.90 mL) = x
    [conc](58.90) (10E-3)= x
    [conc](0.0589)= x
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