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physic · May 14, 2012, 04:58 AM

is there any other ways to solve this natural logarithm: $\ln {(a b)}$
for example
$\ln {ab}=\ln {a} \ln {b}$

ebaines · May 14, 2012, 05:47 AM

Originally Posted by physic

is there any other ways to solve this natural logarithm: $\ln {(a b)}$
for example
$\ln {ab}=\ln {a} \ln {b}$

I think the property you are looking for is: $\log(ab) = \log(a) + \log(b)$ . This applies to all logarithms, regardless of base, including natural logs. Hence $\ln (ab) = \ln (a) + \ln (b)$ .