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How do you find the vertex, focus, and directrix of parabolas?
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I don't really understand this concept, so thorough examples would be much appreciated. :D 1. y^2=8x 2. x^2 + 8y + 16 = 0 ... and Find an equation of the parabola that satisfies the given conditions. 3. Focus (0,1), directrix y = 7
Find the vertex, focus, and directrix of (x+2)^2 = 12y
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It is just about in the standard form of (x-h)^2 = 4p(y-k). My problem is getting 12y into the 4p(y-k) form. I'm dying over here. Any help would be monumental.
Finding vertex, focus, equations of axis of symmetry and directrix of parabolas
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I am working with parabolas and I completely don't understand it. I need to fine the vertex and focus, the axis of symmetry and directrix and the direction of opening of the parabola. I also have to find the length of the latus rectum. I just need a sense of direction to be able to get started and...
How to find focus, when the vertex is know
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(x+4)^2=16(y+2) find the vertex, focus, and directix of the parabola. Graph the equation. I got the vertex, how do find the focus and directix.
I need to find the distance from the focus to the vertex of a parabola
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My question is how can I find the distance from the focus to the vertex of a parabola with the given equation y^2=-10x. Can someone please explain and help me with the answer?? View more questions Search
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