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    __sarah__'s Avatar
    __sarah__ Posts: 20, Reputation: 1
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    Nov 27, 2004, 03:05 PM
    [HELP]gr11 chemistry - predicting chemical reactions and balancing chemical equations
    hey can nebody help me with my chemistry hmwk? i dun really get it... :confused: thanks!

    For each of the following reactions, determine what the products of each reaction will be. When you have predicted the products, balance the equation and use a table of solubility products to determine which of the products (if any) will precipitate. Assume all reactions take place in water.

    3) NaC2H3O2 + H2SO4 -->

    4) Cu(OH)2 + H3PO4 -->

    6) Zn + H2CO3 -->

    For each of the following questions, classify the reaction type (synthesis, decomposition, combustion, single replacement, double replacement, or other) and predict the balanced chemical equation. Provide a word equation as well.

    6. Sulfuric acid is neutralized by aqueous sodium hydroxide.

    9. Propane burns in air.

    10. Na2CO3(aq) + HCl(aq) --> NaCl(aq) + CO2(g) + H2O(l)

    Indicate which of the following double displacement reactions will go to completion, and circle what the product of the reaction will be (if any). You may want to consult a list of Ksp values to solve these problems.

    1)NaOH + CaBr2 -->

    Will this reaction occur? ____

    2)Pb(NO3)2 + HCl -->

    Will this reaction occur? ____

    3)Na2CO3 + KF -->

    Will this reaction occur? ____

    4)AgNO3 + CuSO4 -->

    Will this reaction occur? ____

    5)AgF + NiCl2 -->

    Will this reaction occur? ____
    bluedicius's Avatar
    bluedicius Posts: 20, Reputation: 1
    New Member

    Nov 27, 2004, 08:00 PM
    Reaction type
    Reaction type is pretty straight forward, there are key things to look for.
    Anything dealing with propane or a gas will most likely be a combustion reaction. Another way to know is that a combustion reaction will result in the production of C20 and H2O.
    Decompositon is when you have a compound produces two more substances.
    Oka, Here's a simple way to remember:

    E + E --> C
    Element + element --> compound
    i.e.. 2Na + Cl2 --> 2NaCl
    So you'll have a product which is a combination of the two reactants.

    Decomposition Reaction
    C --> E + E
    Pretty much a reverse of the above.
    i.e.. 2HgO --> 2Hg + O2

    Combustion (think of 'burn')
    Hydrocarbon + O2(g) --> CO2(g) + H2O(g)
    The O2(g) --> CO2(g) + H2O(g) will always remain the same, never change, in these reactions.

    Single and Double Replacement are really simple and straight forward.
    Single Replacement
    E + C --> new E + new C
    So i.e..
    Cu(s) + ZnO(s) --> CuO(s) + Zn(s)
    You swap the Cu and the Zn, you do this because they are both 'positive'

    Double Replacement
    C + C --> newC + newC
    i.e.. NaCl(s) + KBr(s) --> NaBr + KCl
    You can swap either the positives or the negatives that are before the arrow.
    In this case the two positives are swapped again. Na and K to form the two new compounds.

    So when you look at a question, write out what you know, figure out what you need to know and what needs to be formed.

    Na2CO3(aq) + HCl(aq) --> NaCl(aq) + CO2(g) + H2O(l)
    Aqueous sodium carbonate + aqueous hydrochloric acid --> sodium chloride + carbon dioxide + water
    You have compound+compound --> compound + element + element
    Think about it...

    Once you learn the types of reactions everything will come easier.
    Like you asked what about
    Zn + H2CO3 -->
    You have an element + compound
    So you're going to have a single replacement reaction occurring, right?
    You need a new element and a new compound to be formed.
    Think you can figure it out?

    I know this isn't much help but I hope it gave you a start. If you're confused about anything let me know.
    This is a great site to help you out, so check it out if in doubt okay.

    Good luck.
    __sarah__'s Avatar
    __sarah__ Posts: 20, Reputation: 1
    New Member

    Nov 28, 2004, 09:04 PM
    Thanks for the site.. I will look over it :)

    How do I find a tutor? Therez no results.. lol
    bluedicius's Avatar
    bluedicius Posts: 20, Reputation: 1
    New Member

    Nov 29, 2004, 11:12 AM
    You want to find a tutor?
    __sarah__'s Avatar
    __sarah__ Posts: 20, Reputation: 1
    New Member

    Nov 30, 2004, 04:23 PM
    Yea.. I want to find one on that site... but that's OK.. and thanks for your help
    bluedicius's Avatar
    bluedicius Posts: 20, Reputation: 1
    New Member

    Nov 30, 2004, 05:39 PM
    All right, good luck. There are some good sites with tutors, but I don't know the names right now.

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