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jklasd · Feb 14, 2007, 06:40 PM

How do I do this problem?
(6-2i)(5+i)

Capuchin · Feb 14, 2007, 11:22 PM

$(a+b)(c+d) = ac+ad+bc+bd$

using this it should be easy.

asterisk_man · Feb 15, 2007, 06:30 PM

Also, I assume you're using i as in $i\equiv\sqrt{-1}$ so don't forget that $i*i=i^2=-1$ . That will help you simplify the solution some.

katie_kay · Feb 17, 2007, 01:20 PM

What I was taught was to use the FOIL method to do those kinds of problems. First, Outside, Inside Last.

Take 6*5, 6*i, -2i*5, and -2i*i put them in order as you multiplied and simplify.