vfox18 Posts: 1, Reputation: 1 New Member #1 Nov 8, 2011, 07:31 PM
optimization precalculus?
A builder wishes to construct a warehouse with a square front and a volume of 500 cubic meters. Find a formula in terms of x for the total construction cost C(x) of the warehouse.
 Unknown008 Posts: 8,076, Reputation: 723 Uber Member #2 Nov 8, 2011, 09:48 PM
Let x be the side of the square front.

x^2 is the area of the square front.

Let l be the length of the base, then xy is the area of the base.

The total area of the warehouse, for 4 walls and a roof is thus: $2x^2 + 3xy$

The volume of the warehouse is given by $500 = x^2y$

The construction, I assume, is based on the area (amount of concrete or other materials needed). Use the second equation with volume to get the area in terms of x only.

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