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    chels114's Avatar
    chels114 Posts: 1, Reputation: 1
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    #1

    Oct 12, 2011, 04:54 PM
    sin^2x=cosx-1
    How do I solve this, answer in degrees?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Oct 13, 2011, 01:26 AM
    You should have your basic identities with you, and one of them is:



    Use one of these and you would get something just like a quadratic equation to solve. That would be easy :)

    Can you post what you get? :)
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #3

    Oct 13, 2011, 06:38 AM
    A minor correction: cos(2A) = 1 - 2 sin^2(A)

    However, here's another way: use sin^2(x) = 1 - cos^2(x), then apply the quadratic equation to solve for cos(x).
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Oct 13, 2011, 06:50 AM
    Oops, typo :o

    And somehow, I read it as sin squared 2x...
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