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    mr.westforysth's Avatar
    mr.westforysth Posts: 1, Reputation: 1
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    #1

    Jun 7, 2011, 04:16 PM
    Need help to work a 9th grade algebra proble,
    CAROL has three times as many 10 dollar bills as 5 dollar bills. She has a total of $350. How many 5 dollar bills does carol have?
    Wondergirl's Avatar
    Wondergirl Posts: 39,354, Reputation: 5431
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    #2

    Jun 7, 2011, 04:32 PM

    Did you draw a picture? Have you figured out the equation?
    Alty's Avatar
    Alty Posts: 28,317, Reputation: 5972
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    #3

    Jun 7, 2011, 04:41 PM

    Mr.Westforysth, we don't do homework on this site. We're more then willing to help you through it, but you have to make an effort. It's a rule of this site.

    Another rule is that unhelpful/disagree ratings are for factually incorrect info only. Let me explain. If someone said the sky is orange, you could give an unhelpful rating. That statement isn't accurate (true). Your negative rating of Wondergirls post is against the rules of this site.

    So, you've broken two rules already. Not a great start.

    Read the rules, do the work for your question. We can look at what you've figured out, help direct you, tell you where you went wrong. We won't do the work for you. After all, this is your homework. You need to learn it. :)
    Wondergirl's Avatar
    Wondergirl Posts: 39,354, Reputation: 5431
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    #4

    Jun 7, 2011, 04:49 PM

    Unhelpful/disagree ratings are sure-fire ways to push people away from helping you.
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #5

    Jun 8, 2011, 09:35 AM

    Mr. W:

    I won't solve your homework for you eaither, but I am willing to help you think through the process for solving this problem by working a slightly different problem:

    Suppose Joe has twice as many dollar bills as quarters, and a total of $22.50; how many dollar bills does Joe have?

    Let's let D = the number of doillar bills and Q = the number of quarters. Since there are twice as many dollar bills as quarters, you have

    D = 2Q

    And since the value of each dollar is $1 and the value of each quarter is $0.25, you have

    $1 x D + $0.25 x Q = $22.50

    So now you have two equations in two unknowns. To solve you can substitue the first equation into the second so that you're only working in one variable:

    $1 x 2Q + $0.25 x Q = $22.50

    Combine terms:

    $2.25 x Q = $22.5

    Divide through by $2.25:

    $2.25Q/$2.25 = $22.5/$2.25 = 10
    Q = 10.

    Now that we know the value of Q, we can solve for D from the first equation:

    D = 2Q = 20.

    Hope this helps. Post back with the answer you get for your problem and we'll check it for you.

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